Como testar o contexto usando spring?

@PersistenceContext
private EntityManager entityManager;

18:41:57,753 ERROR LazyInitializationException:42 - failed to lazily initialize a collection of role

import javax.persistence.EntityManager;
import javax.persistence.EntityManagerFactory;

import junit.framework.TestCase;

import org.springframework.context.ApplicationContext;
import org.springframework.orm.jpa.EntityManagerFactoryUtils;
import org.springframework.orm.jpa.EntityManagerHolder;
import org.springframework.transaction.support.TransactionSynchronizationManager;

import br.mil.eb.dgp.avaliacao.test.SpringContextLoad;

public abstract class BaseTest extends TestCase {

	private ApplicationContext context = null;

	private EntityManagerFactory entityManagerFactory;

	public BaseTest(final String name) {
		super(name);
	}

	@Override
	protected void setUp() throws Exception {
		super.setUp();
		this.context = SpringContextLoad.getInstance(this.getContextFiles()).getContext();
		entityManagerFactory = (EntityManagerFactory) context.getBean("entityManagerFactory");
		EntityManager entityManager = EntityManagerFactoryUtils.getTransactionalEntityManager(entityManagerFactory);
		TransactionSynchronizationManager.bindResource(entityManagerFactory, new EntityManagerHolder(entityManager));
	}

	@Override
	protected void tearDown() throws Exception {
		super.tearDown();
		EntityManagerHolder entityManagerHolder = (EntityManagerHolder) TransactionSynchronizationManager
				.unbindResource(entityManagerFactory);
		EntityManagerFactoryUtils.closeEntityManager(entityManagerHolder.getEntityManager());
		context = null;
	}

	protected Object getBean(final String beanName) {
		if (null == beanName || 0 == beanName.trim().length())
			throw new IllegalArgumentException("Nome do bean não informado.");
		return this.context.getBean(beanName);
	}

	protected String[] getContextFiles() {
		return new String[] { "application.xml" };
	}

	protected ApplicationContext getApplicationContext() {
		return this.context;
	}
	
}