Consumir Web Service (HTTP em ISS) em java

Programação Java
#1

Preciso de ajuda para consumir meu WebService o mesmo tem o seguinte codigo SOAP

POST /webservice2/URANovoFax.asmx HTTP/1.1
Host: civic
Content-Type: text/xml; charset=utf-8
Content-Length: length
SOAPAction: “http://tempuri.org/RetornaMsg”

<?xml version="1.0" encoding="utf-8"?>

<soap:Envelope xmlns:xsi=“http://www.w3.org/2001/XMLSchema-instance” xmlns:xsd=“http://www.w3.org/2001/XMLSchema” xmlns:soap=“http://schemas.xmlsoap.org/soap/envelope/”>
soap:Body

string

</soap:Body>
</soap:Envelope>
HTTP/1.1 200 OK
Content-Type: text/xml; charset=utf-8
Content-Length: length

<?xml version="1.0" encoding="utf-8"?>

<soap:Envelope xmlns:xsi=“http://www.w3.org/2001/XMLSchema-instance” xmlns:xsd=“http://www.w3.org/2001/XMLSchema” xmlns:soap=“http://schemas.xmlsoap.org/soap/envelope/”>
soap:Body

int

</soap:Body>
</soap:Envelope>

Eu estou tentando acessar o mesmo com o seguinte código java:

package webservice;

import java.net.;
import java.io.;

public class WebService {

private static String strNome = "4031123456";


  public static void main(String[] args) {

	  try {

	      String xmldata = "<?xml version=\"1.0\" encoding=\"utf-8\"?>" +
	      			   "<soap:Envelope xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\" xmlns:soap=\"http://schemas.xmlsoap.org/soap/envelope/\">"+
	      			   "<soap:Body>"+
	      			   "<RetornaMsg xmlns=\"http://tempuri.org/\">"+
	      			   "<strNome>" +
	      			   		strNome +
	      			   "</strNome>"+
	      			   "</RetornaMsg>"+
	      			   "</soap:Body>"+
		   			   "</soap:Envelope>";
	      String xmldata2 = "strNome=" + strNome;
	      //Create socket
	      String hostname = "civic";
	      int port = 80;
	      InetAddress  addr = InetAddress.getByName(hostname);
	      Socket sock = new Socket(addr, port);

	      //Send header
	      String path = "/webservice2/URANovoFax.asmx";
	      BufferedWriter  wr = new BufferedWriter(new OutputStreamWriter(sock.getOutputStream(),"UTF-8"));
	      // You can use "UTF8" for compatibility with the Microsoft virtual machine.
	      wr.write("POST " + path + " HTTP/1.0\r\n");
	      wr.write("Host: " + hostname + "\r\n");
	      wr.write("Content-Length: " + xmldata.length() + "\r\n");
	      wr.write("Content-Type: text/xml; charset=\"utf-8\"\r\n");
	      wr.write("SOAPAction: http://tempuri.org/RetornaMsg");
	      wr.write("\r\n");

	      //Send data
	      wr.write(xmldata);
	      wr.flush();

	      // Response
	      BufferedReader rd = new BufferedReader(new InputStreamReader(sock.getInputStream()));
	      String line;
	      String resp="";
	      System.out.println("Request:");
	      System.out.println(xmldata.replace("><",">\n<"));
	      System.out.println("Response:");
	      while((line = rd.readLine()) != null){
	    	  resp+=line;
	    	  System.out.println(line);
	      }
	    } catch (Exception e) {
	      e.printStackTrace();
	    }
  }
}

Só que a resposta do servidor nunca vem.

#2

Removendo a linha

wr.write(“SOAPAction: http://tempuri.org/RetornaMsg”);

o servidor respondeu:

HTTP/1.1 500 Internal Server Error.
Server: Microsoft-IIS/5.0
Date: Mon, 26 May 2008 14:31:02 GMT
X-Powered-By: ASP.NET
X-AspNet-Version: 1.1.4322
Cache-Control: private
Content-Type: text/xml; charset=utf-8
Content-Length: 483

<?xml version="1.0" encoding="utf-8"?>

<soap:Envelope xmlns:soap=“http://schemas.xmlsoap.org/soap/envelope/” xmlns:xsi=“http://www.w3.org/2001/XMLSchema-instance” xmlns:xsd=“http://www.w3.org/2001/XMLSchema”>
soap:Body
soap:Fault
soap:Client
Unable to handle request without a valid action parameter. Please supply a valid soap action.

</soap:Fault>
</soap:Body>
</soap:Envelope>

O que é isso?

#3

Gera através do WSDL disponibilizado, vai te dar menos trabalho.

#4

Como faço isso?

#5

Axis, Axis2, CXF, JAX-WS, Eclipse, Netbeans…

#6