Arquivo Discussoes de Programacao e Tecnologia 
Tenho esta consulta
SELECT (MAX("data_hora") - MIN("data_hora")) AS "media" , "id_player"
FROM "zanzar_midia" AS "ZanzarMidia"
WHERE ("nome_campanha" LIKE 'MASP15Ba_00000.png'
AND "data_hora" >= '2022-04-01 00:00:00' AND "data_hora" <= '2022-04-03 23:59:59' AND "longitude" != 0 AND "latitude" != 0)
group by "id_player";
Que retorna estas informações
Como pegar a media total de horas por id_player?
Tenho que colocar em node
Aplicar um AVG das horas com um GROUP BY pelo id do player não funciona?
Tentei assim
SELECT
avg((MAX("data_hora") - MIN("data_hora"))),
"id_player"
FROM "zanzar_midia" AS "ZanzarMidia"
WHERE
("nome_campanha" LIKE 'MASP15Ba_00000.png'
AND "data_hora" >= '2022-04-01 00:00:00'
AND "data_hora" <= '2022-04-03 23:59:59'
AND "longitude" != 0
AND "latitude" != 0)
group by "id_player"
order by "id_player" asc;
Mas deu erro
Consegui assim
select avg(retorno."maxMin") media
from (
SELECT
MAX("data_hora") - MIN("data_hora") "maxMin",
"id_player"
FROM "zanzar_midia" AS "ZanzarMidia"
WHERE
("nome_campanha" LIKE 'MASP15Ba_00000.png'
AND "data_hora" >= '2022-04-01 00:00:00'
AND "data_hora" <= '2022-04-03 23:59:59'
AND "longitude" != 0
AND "latitude" != 0)
group by "id_player"
order by "id_player" asc
) retorno;