Erro apos validacao do login

Ola galera, apos validar o usuario, para redirecionar a pagina apropriada, ele volta retorna esse erro no navegador:

[quote]An Error Occurred:

String index out of range: 0
[/quote]

E no console ele retorna esse erro:

SEVERE: Error Rendering View[/pages/protected/index.xhtml] java.lang.StringIndexOutOfBoundsException: String index out of range: 0 at java.lang.String.charAt(Unknown Source) at com.sun.faces.application.view.MultiViewHandler.getResourceURL(MultiViewHandler.java:333) at org.primefaces.renderkit.CoreRenderer.getResourceURL(CoreRenderer.java:76) at org.primefaces.renderkit.OutcomeTargetRenderer.getTargetURL(OutcomeTargetRenderer.java:91) at org.primefaces.component.menu.BaseMenuRenderer.encodeMenuItem(BaseMenuRenderer.java:78) at org.primefaces.component.tieredmenu.TieredMenuRenderer.encodeMenuContent(TieredMenuRenderer.java:104) at org.primefaces.component.tieredmenu.TieredMenuRenderer.encodeSubmenu(TieredMenuRenderer.java:166) at org.primefaces.component.tieredmenu.TieredMenuRenderer.encodeMenuContent(TieredMenuRenderer.java:123) at org.primefaces.component.tieredmenu.TieredMenuRenderer.encodeMenu(TieredMenuRenderer.java:77) at org.primefaces.component.menubar.MenubarRenderer.encodeMarkup(MenubarRenderer.java:52) at org.primefaces.component.menu.BaseMenuRenderer.encodeEnd(BaseMenuRenderer.java:39) at javax.faces.component.UIComponentBase.encodeEnd(UIComponentBase.java:883) at javax.faces.component.UIComponent.encodeAll(UIComponent.java:1659) at javax.faces.render.Renderer.encodeChildren(Renderer.java:168) at javax.faces.component.UIComponentBase.encodeChildren(UIComponentBase.java:853) at javax.faces.component.UIComponent.encodeAll(UIComponent.java:1652) at javax.faces.component.UIComponent.encodeAll(UIComponent.java:1655) at javax.faces.component.UIComponent.encodeAll(UIComponent.java:1655) at com.sun.faces.application.view.FaceletViewHandlingStrategy.renderView(FaceletViewHandlingStrategy.java:399) at com.sun.faces.application.view.MultiViewHandler.renderView(MultiViewHandler.java:131) at com.sun.faces.lifecycle.RenderResponsePhase.execute(RenderResponsePhase.java:121) at com.sun.faces.lifecycle.Phase.doPhase(Phase.java:101) at com.sun.faces.lifecycle.LifecycleImpl.render(LifecycleImpl.java:139) at javax.faces.webapp.FacesServlet.service(FacesServlet.java:313) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:304) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:210) at com.teste.ems2.filter.LoginCheckFilter.doFilter(LoginCheckFilter.java:69) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:243) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:210) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:240) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:164) at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:462) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:164) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:100) at org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:562) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:118) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:395) at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:250) at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:188) at org.apache.tomcat.util.net.JIoEndpoint$SocketProcessor.run(JIoEndpoint.java:302) at java.util.concurrent.ThreadPoolExecutor.runWorker(Unknown Source) at java.util.concurrent.ThreadPoolExecutor$Worker.run(Unknown Source) at java.lang.Thread.run(Unknown Source)

E o codigo do meu LoginCheckFilter

[code]public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException {
HttpServletRequest req = (HttpServletRequest) request;
HttpSession session = req.getSession();

	if (session.isNew()) {
		doLogin(request, response, req);
		return;
	}

	Utilisateur user = (Utilisateur) session.getAttribute("user");

	if (user == null && !allowedURIs.contains(req.getRequestURI())) {
		System.out.println(req.getRequestURI());
		doLogin(request, response, req);
		return;
	}

	chain.doFilter(request, response);  // erro  linha 69
}[/code]

O que estou usando:

[quote]primefaces 3.5
jsf-api-2.0.4-b09
jsf-impl-2.0.4-b09
hibernate 4.1.10
JPA 2.0[/quote]

Não estou sabendo o que esta acontecendo pois aparentemente esta tudo certo, alguém tem alguma idéia do problema?!!

Obrigado galera.

Normalmente este erro ocorre por você estar tentando pegar o índice 0 da sua String.

Mas em seu código que postou não há indícios para este tipo de erro.

Te aconselho a debugar sua aplicação ao preencher os campos de login a acionar o submit.

Lucas, adicionei o trace e olha o resultado:

11:17:33,826 TRACE BasicBinder:83 - binding parameter [1] as [VARCHAR] - admin@admin 11:17:33,841 TRACE BasicExtractor:72 - Found [1] as column [id17_] 11:17:33,841 TRACE BasicExtractor:72 - Found [admin@admin] as column [login17_] 11:17:33,841 TRACE BasicExtractor:72 - Found [andriel] as column [password17_] 11:17:33,841 TRACE BasicExtractor:67 - Found [null] as column [person5_17_] 11:17:33,841 TRACE EnumType:448 - Returning [ADMIN] as column [roleUser17_]

Então isso quer dizer que consigo encontrar o usuario, logo o submit não esta passando valores vazios.

Abraço.

[quote=andrielc]Lucas, adicionei o trace e olha o resultado:

11:17:33,826 TRACE BasicBinder:83 - binding parameter [1] as [VARCHAR] - admin@admin 11:17:33,841 TRACE BasicExtractor:72 - Found [1] as column [id17_] 11:17:33,841 TRACE BasicExtractor:72 - Found [admin@admin] as column [login17_] 11:17:33,841 TRACE BasicExtractor:72 - Found [andriel] as column [password17_] 11:17:33,841 TRACE BasicExtractor:67 - Found [null] as column [person5_17_] 11:17:33,841 TRACE EnumType:448 - Returning [ADMIN] as column [roleUser17_]

Então isso quer dizer que consigo encontrar o usuario, logo o submit não esta passando valores vazios.

Abraço.[/quote]

Isso mesmo, sua aplicação encontra o usuário.

O problema deve estar em algum método na sua Action ou Controller.