Generics: Informações a respeito do atributo[Resolvido]

public static <T>String toString(Iterable<T> iterable, String separator){
 		if(iterable == null || separator == null)
 			return null;
 		
 		StringBuilder sb = new StringBuilder("");
 		for(Iterator<T> it = iterable.iterator(); it.hasNext();) {
 			sb.append(it.next());
 			if(it.hasNext())
 				sb.append(separator);
 		}
 		return sb.toString();
 	}

public static <T>String toString(Iterable<T> iterable, Class<T> klass, String separator)...

public static <T>String toDeepString(T[] array , String separator){
		return toDeepString(Arrays.asList(array), separator);
	}
	public static <T>String toDeepString(Iterable<T> iterable, String separator){
		if(iterable == null || separator == null)
			return null;
		
		StringBuilder sb = new StringBuilder("");
		for(Iterator<T> it = iterable.iterator(); it.hasNext();) {
			T elem = it.next();
			if(elem instanceof Iterable<?>)
				sb.append(toDeepString((Iterable<?>)elem, separator));
			else if(elem.getClass().getComponentType() != null)
				sb.append(toDeepString((Object[])elem, separator));
			else
				sb.append(elem);
			
			if(it.hasNext())
				sb.append(separator);
		}
		return sb.toString();
	}