Primeiro servlet

1 resposta
B

nao entendi o porque do erro!

alguem pode me ajudar, por favor?

CATALINA_HOME = C:\Arquivos de programas\Tomcat 5.5

CLASS_PATH = .;%JAVA_HOME%;C:\Arquivos de programas\Java\jdk1.5.0_01\lib\servlet-api.jar

JAVA_HOME = C:\Arquivos de programas\Java\jdk1.5.0_01

PATH = %PATH%;%JAVA_HOME%\\bin

o xml está em C:\Arquivos de programas\Tomcat 5.5\webapps\ROOT\ch1\WEB-INF

o arquivo Ch1Servlet.class está em C:\Arquivos de programas\Tomcat 5.5\webapps\ROOT\ch1\WEB-INF\classes

o xml é

<web-app xmlns="http://java.sun.com/xml/ns/j2ee" xmlnssi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd" version="2.4"> 

<servlet> 
<servlet-name>chapter1</servlet-name> 
<servlet-class>Ch1Servlet</servlet-class> 
</servlet> 

<servlet-mapping> 
<servlet-name>chapter1</servlet-name> 
<url-pattern>/serv1</url-pattern> 
</servlet-mapping> 

</web-app>

o servlet é

import javax.servlet.*; 
import javax.servlet.http.*; 
import java.io.*; 

public class Ch1Servlet extends HttpServlet{ 


public void doGet(HttpServletRequest req, HttpServletResponse resp) throws IOException{ 

PrintWriter out = resp.getWriter(); 

java.util.Date today = new java.util.Date(); 

out.println("<html>" + "<body>" + "<h1 align = center>Chapter1 Servlet</h1>" + "<br>" + today +"</body>" +"</html>"); 

} 

}

o erro é

HTTP Status 404 - /ch1/serv1

--------------------------------------------------------------------------------

type Status report

message /ch1/serv1

description The requested resource (/ch1/serv1) is not available.

--------------------------------------------------------------------------------

Apache Tomcat/5.5.17

ja tentei http://localhost:8080/serv1, http://localhost:8080/ch1/serv1
e nada...

:sad:

1 Resposta

G

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Criado 31 de julho de 2006
Ultima resposta 31 de jul. de 2006
Respostas 1
Participantes 2