[Resolvido] File, ler XML remoto

http://java.sun.com/j2ee/sdk_1.3/techdocs/api/javax/servlet/ServletContext.html#getResourceAsStream%28java.lang.String%29

Tem como pegar o ServletContext a partir do request?

como posso fazer

ServletContext servletContext = request.getSession().getServletContext()

por algum motivo assim não deu certo, ai passei como parametro para o metodo e aparentemente deu certo

mas agora o problema é que o

InputStream input = sc.getResourceAsStream(path);

está retornando null

Dá uma uma lida no javadoc:

getResource

Returns a URL to the resource that is mapped to a specified path. The path must begin with a “/” and is interpreted as relative to the current context root.

This method allows the servlet container to make a resource available to servlets from any source. Resources can be located on a local or remote file system, in a database, or in a .war file.

The servlet container must implement the URL handlers and URLConnection objects that are necessary to access the resource.

This method returns null if no resource is mapped to the pathname.

Some containers may allow writing to the URL returned by this method using the methods of the URL class.

The resource content is returned directly, so be aware that requesting a .jsp page returns the JSP source code. Use a RequestDispatcher instead to include results of an execution.

This method has a different purpose than java.lang.Class.getResource, which looks up resources based on a class loader. This method does not use class loaders.

Não entendi muito bem…

se quiser me ajudar!

o meu código está abaixo:

StringBuffer url = request.getRequestURL();
		int limitador = url.indexOf("financeiro/");
		String path = url.substring(0, limitador)+"emailCartaFornecedor.xml";
		URL u = new URL(path);
		URLConnection connection = u.openConnection();
		System.out.println(sc);
		InputStream input = sc.getResourceAsStream("/sistema/financeiro/emailCartaFornecedor.xml");
		System.out.println(input);

obrigado

consegui:

private InputStream getArquivo(HttpServletRequest request) throws IOException{ StringBuffer url = request.getRequestURL(); int limitador = url.indexOf("financeiro/"); String path = url.substring(0, limitador)+"emailCartaFornecedor.xml"; URL u = new URL(path); URLConnection connection = u.openConnection(); connection.connect(); return connection.getInputStream(); }