Boa noite,
Estou me deparando com uma batalha praticamente impossível de vencer com os meus malditos LazyInitializationException e não estou conseguindo utilizar o OpenSessionInView.
Atualmente tenho uma classe de configuração (ao invés do xml) do meu Spring e tentei acrescentar no xml, conforme:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
version="2.5">
<context-param>
<param-name>br.com.caelum.vraptor.provider</param-name>
<param-value>xxx.DnocsSpringProvider</param-value>
</context-param>
<filter>
<filter-name>vraptor</filter-name>
<filter-class>br.com.caelum.vraptor.VRaptor</filter-class>
</filter>
<filter-mapping>
<filter-name>vraptor</filter-name>
<url-pattern>/*</url-pattern>
<dispatcher>FORWARD</dispatcher>
<dispatcher>REQUEST</dispatcher>
</filter-mapping>
<filter>
<filter-name>openSessionInViewFilter</filter-name>
<filter-class>org.springframework.orm.jpa.support.OpenEntityManagerInViewFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>openSessionInViewFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<servlet>
<servlet-name>WebServicesServlet</servlet-name>
<servlet-class>xxx.services.WebServicesServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>WebServicesServlet</servlet-name>
<url-pattern>/services/*</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.htm</welcome-file>
<welcome-file>index.jsp</welcome-file>
<welcome-file>default.html</welcome-file>
<welcome-file>default.htm</welcome-file>
<welcome-file>default.jsp</welcome-file>
</welcome-file-list>
</web-app>
Mas mesmo assim, ainda pego sempre
org.hibernate.LazyInitializationException: could not initialize proxy - no Session
Como devo prosseguir por favor para o OpenSessionInView funcionar?
Obrigado.