Web.xml e webwork

1 resposta
kartler

Em um ambiente compartilhado a qual tem um tomcat instalado para vários clientes é correto configurar o web.xml de minha aplicação para trabalhar com o webwork desta forma.

Obs:Tomcat 5.28 WEbwork 2.0
Obrigado.

<?xml version="1.0" encoding="ISO-8859-1"?>
<!DOCTYPE web-app PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN" "http://java.sun.com/dtd/web-app_2_3.dtd">
<web-app>

<!--
<?xml version="1.0" encoding="ISO-8859-1"?>
<!DOCTYPE web-app PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN" "http://java.sun.com/dtd/web-app_2_3.dtd">
<web-app>
-->
    <display-name>MeuContexto</display-name>

    <filter>
        <filter-name>container</filter-name>
        <filter-class>com.opensymphony.webwork.lifecycle.RequestLifecycleFilter</filter-class>
    </filter>

    <filter-mapping>
        <filter-name>container</filter-name>
        <url-pattern>/*</url-pattern>
    </filter-mapping>


    <listener>
        <listener-class>com.opensymphony.webwork.lifecycle.ApplicationLifecycleListener</listener-class>
    </listener>

    <listener>
        <listener-class>com.opensymphony.webwork.lifecycle.SessionLifecycleListener</listener-class>
    </listener>

    <servlet>
        <servlet-name>webwork</servlet-name>
        <servlet-class>com.opensymphony.webwork.dispatcher.ServletDispatcher</servlet-class>
    </servlet>

    <servlet>
        <servlet-name>velocity</servlet-name>
        <servlet-class>com.opensymphony.webwork.views.velocity.WebWorkVelocityServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>velocity</servlet-name>
        <url-pattern>*.vm</url-pattern>
    </servlet-mapping>

    <servlet-mapping>
        <servlet-name>webwork</servlet-name>
        <url-pattern>*.action</url-pattern>
    </servlet-mapping>

    <welcome-file-list>
        <welcome-file>index.jsp</welcome-file>
        <welcome-file>default.jsp</welcome-file>
        <welcome-file>index.html</welcome-file>
    </welcome-file-list>

    <taglib>
        <taglib-uri>webwork</taglib-uri>
        <taglib-location>/WEB-INF/webwork.tld</taglib-location>
    </taglib>

    <taglib>
        <taglib-uri>benchmark</taglib-uri>
        <taglib-location>/WEB-INF/taglibs-benchmark.tld</taglib-location>
    </taglib>

    <taglib>
        <taglib-uri>c</taglib-uri>
        <taglib-location>/WEB-INF/c.tld</taglib-location>
    </taglib>
</web-app>

1 Resposta

jack_ganzha

Sim, por que a duvida? No tomcat, cada contexto tem seu proprio classloader, se essa era sua preocupação.

valeuz…

Criado 17 de setembro de 2004
Ultima resposta 19 de set. de 2004
Respostas 1
Participantes 2