estou fazendo alguns testes com spring security e ao tentar gravar no banco está dando esse erro, aparentemente está tudo configurado, podem me ajudar?
public class JPAConfiguration {
@Bean
public LocalContainerEntityManagerFactoryBean entityManagerFactory() {
LocalContainerEntityManagerFactoryBean factoryBean = new LocalContainerEntityManagerFactoryBean();
JpaVendorAdapter vendorAdapter = new HibernateJpaVendorAdapter();
factoryBean.setJpaVendorAdapter(vendorAdapter);
DriverManagerDataSource dataSource = new DriverManagerDataSource();
dataSource.setUsername("root");
dataSource.setPassword("root");
dataSource.setUrl("jdbc:mysql://localhost:3306/base_preconizado");
dataSource.setDriverClassName("com.mysql.jdbc.Driver");
factoryBean.setDataSource(dataSource);
Properties props = new Properties();
props.setProperty("hibernate.dialect", "org.hibernate.dialect.MySQL5Dialect");
props.setProperty("hibernate.show_sql", "true");
props.setProperty("hibernate.hbm2ddl.auto", "update");
factoryBean.setJpaProperties(props);
factoryBean.setPackagesToScan("br.com.preconizado.models");
return factoryBean;
}
@Bean
public JpaTransactionManager transactionManager(EntityManagerFactory emf) {
return new JpaTransactionManager(emf);
}
meu metodo dao
@Repository
@Transactional
public class UsuarioDAO implements UserDetailsService {
@PersistenceContext
private EntityManager manager;
// @Autowired
// public UsuarioDAO usuarioDAO;
// metodo que grava os dados no banco
public void gravar(Usuario usuario) {
manager.persist(usuario);
System.out.println("inserido");
}
public List<Usuario> find() {
List<Usuario> usuarios = manager.createQuery("select u from Usuario u", Usuario.class).getResultList();
return usuarios;
}
}